Discrete Math Contradiction

Discrete Math 1 Tutorial 33 Conjunction, Disjunctive Syllogism

Discrete Math Contradiction. \(a,b\) have no common factor but \(a,b\) have a common factor of \(2\text{.}\) that is, we. Web we have arrived at our contradiction:

Discrete Math 1 Tutorial 33 Conjunction, Disjunctive Syllogism
Discrete Math 1 Tutorial 33 Conjunction, Disjunctive Syllogism

\(a,b\) have no common factor but \(a,b\) have a common factor of \(2\text{.}\) that is, we. Web we have arrived at our contradiction:

Web we have arrived at our contradiction: \(a,b\) have no common factor but \(a,b\) have a common factor of \(2\text{.}\) that is, we. Web we have arrived at our contradiction: